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World news
India
Patiala
07:46 23 July 2020
So Here is an Question
Topic: Complex Number
Question : Find the square root of the 7-24
i (i = iota)
Solution : (x+
i
y)^2 = 7-24
i
:) X^2 - Y^2 +2
i
xy = 7 - 24
i
:) Now equate the terms
:) 2xy = 24. X^2 -Y^2 =7
xy =24/2. ( Putting value
xy=12 of y in this
y = 12/x. It becomes)
X^2 - 7X^2 - 144 =0
(X^2 -16) (X^2 + 9) = 0
:) From here we get
X = ± 4. X = ±3
Answer :) (4 - 3
i)
and (-4+3
i
)
I hope this sol. Will help you alot ...???☺☺☺??
Thank you and have safe day ????
:)
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