# All publications of Tanveer Singh . Patiala , India

### So Here is an Question

### Topic: Complex Number

### Question : Find the square root of the 7-24*i (i = iota)*

### Solution : (x+*i *y)^2 = 7-24*i*

### :) X^2 - Y^2 +2*i*xy = 7 - 24 *i*

### :) Now equate the terms

### :) 2xy = 24. X^2 -Y^2 =7

xy =24/2. ( Putting value

### xy=12 of y in this

### y = 12/x. It becomes)

### X^2 - 7X^2 - 144 =0

### (X^2 -16) (X^2 + 9) = 0

### :) From here we get

### X = ± 4. X = ±3

### Answer :) (4 - 3*i) *and (-4+3*i*)

### I hope this sol. Will help you alot ...???☺☺☺??

### Thank you and have safe day ????

### :)

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