All publications of Tanveer Singh . Patiala , India

So Here is an Question

Topic: Complex Number

Question : Find the square root of the 7-24i (i = iota)

Solution : (x+i y)^2 = 7-24i

:) X^2 - Y^2 +2ixy = 7 - 24 i

:) Now equate the terms

:) 2xy = 24. X^2 -Y^2 =7

xy =24/2. ( Putting value

xy=12 of y in this

y = 12/x. It becomes)

X^2 - 7X^2 - 144 =0

(X^2 -16) (X^2 + 9) = 0

:) From here we get

X = ± 4. X = ±3

Answer :) (4 - 3i) and (-4+3i)

I hope this sol. Will help you alot ...???☺☺☺??

Thank you and have safe day ????

:)