All publications of Tanveer Singh . Patiala , India
So Here is an Question
Topic: Complex Number
Question : Find the square root of the 7-24i (i = iota)
Solution : (x+i y)^2 = 7-24i
:) X^2 - Y^2 +2ixy = 7 - 24 i
:) Now equate the terms
:) 2xy = 24. X^2 -Y^2 =7
xy =24/2. ( Putting value
xy=12 of y in this
y = 12/x. It becomes)
X^2 - 7X^2 - 144 =0
(X^2 -16) (X^2 + 9) = 0
:) From here we get
X = ± 4. X = ±3
Answer :) (4 - 3i) and (-4+3i)
I hope this sol. Will help you alot ...???☺☺☺??
Thank you and have safe day ????
:)
1
+12
+10
13